Robertson and Higgins to contest Wuxi final


Pictures by Monique Limbos

NEIL Robertson and John Higgins will battle it out on Sunday to win the season’s first major ranking event – the Wuxi Classic.

The Australian and the Scot both eased through to the final with comfortable 6-2 victories in their semi-final clashes against Robert Milkins and Matthew Stevens respectively.

It will be the second time this month the pair have met in a final after Higgins beat Robertson in the Bulgarian Open – this season’s opening PTC event.

Robertson, bidding for back to back majors in China after winning the China Open earlier this year, gained revenge on Milkins who defeated him in the first round of the World Championship in April.

The world number one stormed into a 4-0 lead with top breaks of 71, 51, 59 and 77 before Milkins took the next two frames. But there was no stopping Robertson as he completed the win taking the final two frames including a high break of 92.

Higgins continued his strong start to the campaign with a convincing win over Stevens. The four-times world champion won the first three frames before he extended his lead further potting a long re-spotted black in the fourth.

Higgins then took the fifth frame after the mid-session interval before Stevens avoided a potential whitewash defeat  by winning back to back frames. But Higgins won the eighth frame to seal the contest.

The winner of Sunday’s final will net the cash-winning prize of £80,000 and a tournament total of 7,000 ranking points.

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